Euler's Formula on Complex Numbers - Expii
Euler's formula is the statement that e^(ix) = cos(x) + i sin(x). When x = π, we get Euler's identity, e^(iπ) = -1, or e^(iπ) + 1 = 0. Isn't it amazing that the numbers e, i, π, 1, 0 are related in such a simple way?.